Ask question

Ask question

All categories

3 years ago

15

Beatrice has 0.28 in her pocket. What percent of dollars does beatrice have

1 answer:

yulyashka [42]3 years ago

5 0

Answer:

28 is equal to 28/100. Therefore, it is 28 percent.

You might be interested in

Find the value of 1 x in two parallel lines

Mazyrski [523]

Answer:

18

Step-by-step explanation:

4x + 5x = 180

10x = 180

x = 18

5 0

2 years ago

Read 2 more answers

Elena went 60 meters in 50 seconds. Noah went 50 meters in 10 seconds. Elena and Noah both moved at a constant speed. Who went f

photoshop1234 [79]

Noah because he went way faster

6 0

3 years ago

Solve for the variable X=5y for y

SSSSS [86.1K]

y= x/5. or x over 5. you are trying to isolate y. in other words you are trying to get y all by itself on one side of the equation. To do that, you need to divide 5 by both sides. It is important to do what you do on one side to the other because that keeps that values of the equation the same.

7 0

4 years ago

Give the equation of a line that goes through the point ( − 24 , 2 ) and is perpendicular to the line 8 x + 3 y = − 6 . Give you

Studentka2010 [4]

Answer:

$y=\frac{3}{8}x+11$

Step-by-step explanation:

To find a line that is perpendicular to 8x + 3y = -6 and goes through (-24, 2), lets first find what the line's slope would be.

We can find this by finding the slope of 8x + 3y = -6 and taking the negative reciprocal of it.

We can find the slope of that line by putting it in slope-intercept form:

8x + 3y = -6

Subtract 8x from both sides.

3y = -6 - 8x

Divide both sides by 3.

$y=-\frac{6}{3}-\frac{8}{3}x$

$y=-\frac{8}{3}x-2$

So the slope of that line would be -8/3.

The negative reciprocal of -8/3 would be 3/8.

Now we know that the new line would have to pass through the point (-24, 2). We can use this point and write the equation in point-slope form:

$y-2=\frac{3}{8}(x+24)$

Now lets change this into slope-intercept form. Add 2 to both sides.

$y=\frac{3}{8}(x+24) +2$

Distribute the 3/8.

$y=\frac{3}{8}x+9+2$

Simplify.

$y=\frac{3}{8}x+11$

And now we have our equation in slope-intercept form.

I hope you find this helpful.

5 0

3 years ago

Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i

lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

$A= P(1+\frac{r}{100} )^n$

$\Leftrightarrow 17900=15200(1+\frac{r}{100})^3$

$\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}$

$\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }$

$\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1$

$\Leftrightarrow r=5.60$

Let $t^{th}$ year Joe's income was $19,700.

$\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}$

$\Leftrightarrow 1.296= (1+0.056)^{t-1}$

$\Leftrightarrow 1.296= (1.056)^{t-1}$

$\Leftrightarrow log(1.296)= (t-1)log(1.056)$

$\Leftrightarrow \frac{log(1.296)}{log(1.056)}= (t-1)$

$\Leftrightarrow t-1= 4.75$

$\Leftrightarrow t= 4.75+1$

$\Leftrightarrow t = 5.75$ ≈6

Therefore 6th year his income was $19,700.

8 0

3 years ago