I hope this is right , from what i remember it should be B
Good morning ☕️
Answer:
<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ =
0</h3>
Step-by-step explanation:
Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰
S = i¹ + i² + i³ + . . . + i⁹⁹ + i¹⁰⁰
S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀
then, S is the sum of 100 consecutive terms of a geometric sequence (an)
where the first term a1 = i¹ = i and the common ratio = i
FORMULA:______________________
_______________________________
then
or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1 (we know that i⁴ = 1)
Hence
S = 0
Answer:
(0, 3 )
Step-by-step explanation:
Given the 2 equations
4x + 2y = 6 → (1)
16x - 4y = - 12 → (2)
Multiplying (1) by 2 and adding to (2) will eliminate the x- term
8x + 4y = 12 → (3)
Add (2) and (3) term by term
(8x + 16x) + (4y - 4y) = (12 - 12), that is
24x = 0 ⇒ x = 0
Substitute x = 0 into (1) or (2) and solve for y
Substituting in (1)
4(0) + 2y = 6
0 + 2y = 6
2y = 6 ( divide both sides by 2 )
y = 3
Solution is (0, 3 )
Answer:
Step-by-step explanation:
1) Reflection over
2) The triangles are congruent by SAS, so when is mapped onto , because points and are corresponding, will correspond with .
3) Yes, because , so the triangles are congruent by SAS.
Answer:
Im sure the answer is 40%
<em>GL Deary</em>
<em>Hope I helped!!!</em>
<em><3</em>