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3 years ago

A compact disc has an approximate Radius of 2 3/8 inches, what is the approximate area of a CD

Mathematics

1 answer:

professor190 [17]3 years ago

6 0

Answer:

A≈12.57

r Radius 2

Step-by-step explanation:

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The radius of a circle is 13 in. Find its area in terms of pi

grigory [225]

Answer:

A≈530.93in²

Step-by-step explanation:

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3 years ago

Read 2 more answers

F(x) = -2x²-2x+10, find f(2)

beks73 [17]

Answer:

f(2) = -2

Step-by-step explanation:

Substitute 2 everywhere you see an x so f(2) = -2( $2^{2}$ ) - 2(2) + 10 so

f(2) = -2(4) - 4 + 10, so f(2) = -8-4+10, f(2) = -12+10, f(2) = -2

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3 years ago

Divide 8 2/5 ÷ (-2 1/5)

lesantik [10]

8 2/5 ÷(-2 1/5) = -3.81818181818

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3 years ago

carol's father was 24 years old when carol was born, now he is 4 times as old a carol how old is carol

tensa zangetsu [6.8K]

Answer:

24 - 24 = 0 (carols age past tense)

24 x 4 = 96

96 - 24 = 72 (present tense)

carol is now 72 yr

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2 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

Hence, option (a) 2/3 is your correct answer.

3 0

2 years ago