The mass in kilograms would be: 1.442424
<h2>Steps</h2>
- Standard Form Equation: f(x) = ax² + bx + c
So firstly, since (0,5) is one of our values we can plug it into the standard form equation to solve for the c variable (since 0 will cancel out the a and b variable):

Now we know that the value of c is 5. Next, plug in (-1,12) into the standard form equation and simplify (remember to also plug in 5 for the c variable):

Next, plug (2,15) into the standard form equation and simplify:

Now, with our last two simplified equations we will create a system of equations:

Now, I will be using the elimination method with this system. With the system, add up the equations together and you will get:

From here, we can solve for the a variable. With it, just divide both sides by 3:

Now that we know the value of a, plug it into either equation to solve for the b variable:

<h2>Answer</h2>
Putting all of our obtained values together, your final answer is:

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

And

_________________________________
To find the y-intercept of any equation just need to put 0 (( zero )) instead of the x in the equation...
<h2>
Let's do it....</h2>
_________________________________
In f ( x ) :




Thus :

##############################
In g ( x ) :





Thus :

_________________________________
The positive difference in the y-intercept value of f ( x ) and g ( x ) is :

So write this in the box : 1
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
And we're done....
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
Answer:
Hello,
Step-by-step explanation:

Answer:
I think the answer is 2^2x+6 = 2^6
Step-by-step explanation:
hope this helps if not let me know have a blessed day