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aleksandr82 [10.1K]
2 years ago
9

Y= 3x — 5 what is the slope and y-intercept

Mathematics
2 answers:
Alex_Xolod [135]2 years ago
8 0
4x is the answer for this one





ArbitrLikvidat [17]2 years ago
8 0

Answer:

Slope is 3. Y intercept is -5.

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Landon used a semicircle, a rectangle, and a right triangle to form the figure shown.
pashok25 [27]
I believe the answer is 10
3 0
2 years ago
Plz help with this math question.Thx:) Don't forget to show your work.
sergij07 [2.7K]
You can use any data set in this table (except the row with x) to get the ratio.

so 20/196 is the ratio which equals about .102041

then multiply that decimal by the weight in the x row to see what x is

so 1078(.102041) = 110.000198 just round that to 110. you can also verify that ratio by checking other data points. for instance

490(.102041) = 50.00009 or 50

so you know x is 50 so answer is either b or d

then you know the ratio .102041, so does (10/98) = .102041

or does (98/10) = .102041

if you do the division you will see that (10/98) = .102041

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5 0
3 years ago
Which co-ordinates do you plot to draw the graph of x + 2y = 3 ?
pychu [463]
Just subisute values that will work
one easy way is to make one sides equal to only one of the placeholders, like y, and then lug in values in for x exg
x+2y=3
subtract x from both sides
2y=3-x
divideb bith sides by 2
y=-1/2x+3
subsitute valudes for x and get values for y
if x=2 then
y=-1/2(2)+3
y==-1+3
y=2
when x=2, y=2
when y=0 then y=3
3 0
3 years ago
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
Three students were given the expression shown to simplify.
koban [17]
2-21x+28
-21x +3
Hope it helps
6 0
3 years ago
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