Answer:The hybridisation of C1 and C2 are sp3 and sp2 respectively.
Explanation:
Here the first carbon (C-1) formed four straight single bonds.
Linking to the electron theory (a fig.1 shown below) one electron from 2s orbital moves to the empty 2pz orbital.
The 2s and the three 2p orbitals hybridise and each orbital will be completed by one electron shared mutually with and from N, H, H, and the other C.
C-2 the second carbon has an sp2 because it forms a double bond with oxygen.
In the sp2 hybridisation the 2s orbital hybridises with only two 2p orbitals leaving the other 2p orbital unhybridised. The orbitals in sp2 is to be completed with one more electron each by sharing covalently with the C, O and the other O.
Note: The unhybridised p orbital is completed with the other shared electron of the oxygen. This forms the π bond in the carbon-oxygen double bond. (Fig 2. Shows the electronic arrangements.)
There should be 3 significant figures in the average that you find because there are three significant figures in the weights you are using to find an average.
Answer:
An alternative to this could be 70 isopropyl alcohol. Potassium iodide is what is used to iodize salt, protect the thyroid gland from radioactive iodine, and via a pill taken by mouth treats low iodine levels (especially in the developing world). An alternative to this could be non-iodized salt.
Explanation:
Hope this helps.
Answer:
D.<em>The</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>waves</em><em> </em><em>that</em><em> </em><em>pass</em><em> </em><em>a</em><em> </em><em>point</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>(</em><em>per</em><em>)</em><em> </em><em>second</em>
Answer:
weight of salt = 90 gram,
solubility = 50
sing formula
solubility of solute =
weightofsolventinsaturatedsolution
weightofsoluteinsaturatedsolution
×100
or 50=
weightofsolventinsaturatedsolutio
90gm
×100
so weight of solvent in saturated solution =
50
90gm
×100=180gm
Hence 180 gm of water is required to prepare a saturated solution.