A silver coin with a mass of 14.1g has a density of 10.5 grams

Redox reactions can be written as two half-reactions, focusing on the gain or loss of electrons by one of the chemical substance

lutik1710 [3]

Answer:

C) H⁺

Explanation:

When we are balancing the reaction in an acid medium, hydrogen is balanced using the H⁺ species. This is most likely the intended answer of your question.

When the reaction takes place not in an acid medium, but in an alkaline one, then hydrogen is present as the OH⁻ species. However this option is not given in your question.

Thus the answer is option C).

5 0

3 years ago

Draw the expanded structural formula for the condensed formula (CH3)2CHCH2OCH2CH3 . Draw all hydrogen atoms

prisoha [69]

We have that the Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below

From the Question

(CH3)2CHCH2OCH2CH3

Generally for the condensed formula (CH3)2CHCH2OCH2CH3

We consider that this is a single bond connecting them

We consider

Hydrogen H(1)

Oxygen(8)

Carbon(6)

In conclusion

The Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below.

For more information on this visit

brainly.com/question/24102840

5 0

3 years ago

As a technician in a large pharmaceutical research firm, you need to produce 250. mL of a potassium dihydrogen phosphate buffer

Reika [66]

Answer:

We will need 147.772 mL of KH2PO4 to make this solution

Explanation:

For this case we can give the following equation:

H2PO4 - ⇄ H+ + HPO42-

With following pH- equation:

pH = pKa + log [HPO42-]/[H2PO4-]

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

-0.16 = log [HPO42-]/[H2PO4-]

10^-0.16 = [HPO42-]/[H2PO4-]

0.6918 = [HPO42-]/[H2PO4-]

Let's say the volume of HPO42-= x then the volume of H2PO4- will be 250 mL - x

Since both have a concentration of 1M = 1 mol /L

If we plug this in the equation 0.6918 = [HPO42-]/[H2PO4-]

0.6918 = x / (250 - x)

0.6918*250 - 0.6918x = x

172.95 = 1.6918x

x = 102.228 mL

The volume of HPO42- = 102.228 mL

Then the volume of H2PO4- = 250 - 102.228 = 147.772 mL

To control this we can plug this in the pH equation

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

7.05= 7.21 + log (102.228 / 147.772) = 7.05

We will need 147.772 mL of KH2PO4 to make this solution

3 0

3 years ago

Dana is trying to determine if an unknown sample is a pure substance or not. The sample has a cloudy white color, and it seems e

Firdavs [7]

Answer:

Dana filtered the sample and larger granules of the sample were left behind.

Explanation:

If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.

One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.

Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.

5 0

2 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$