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fenix001 [56]
3 years ago
14

What is the answer of the expression 325-[4x(58-19)+(75 divided by 3

Mathematics
1 answer:
inna [77]3 years ago
4 0
325 - [4(58 - 19) + (75 / 3)]

Divide:

325 - [4(58 - 19) + 25]

Distribute 4:

325 - [232 - 76 + 25]

Subtract:

325 - [156 + 25]

Add:

325 - [181]

Subtract:

144
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a family is staying in a hotel and the total bill for 4 nights is $400. there is a one-time $60 tax fee. what was the nightly ra
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Answer:

Yes. For example, a hotel advertises, “Buy 4 nights, get the 5th night free.” Taking advantage of the deal, a customer purchases 5 nights for $400. Each night of the customer’s 5-night stay is subject to the fee.

Step-by-step explanation:

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2 years ago
When you find 36 is 42% of what number, what are you looking for?​
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dezzzz nuts

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3 years ago
What are the solutions of the equation 6x2 + x-1=0 ?
Aleksandr [31]

Answer:

<u>Options B and D</u>

Step-by-step explanation:

6x² + x - 1 = 0

6x² + 3x - 2x - 1 = 0

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(3x - 1)(2x + 1)

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6 0
1 year ago
Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f
BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = \frac{width}{2}

ME = \frac{0.14}{2}

ME = 0.07

ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}

use p = 0.5

z at 95.8% is 1.727(using calculator)

0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}

\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}

(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}

n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}

n \geq 152.169

So, Option B is true

Hence  we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

6 0
2 years ago
This is an isosceles trapezoid.
Ad libitum [116K]

Answer:

105°

Step-by-step explanation:

X and 75 has to add up to 180

so 180 - 75 = 105°

3 0
2 years ago
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