3 years ago

I WILL GIVE BRAINLIEST

Mathematics

2 answers:

Ainat [17]3 years ago

8 0

Answer:

Graph A represents y=(3/4)x-3

which has the slope= 3/4 and the y-intercept= -3

vazorg [7]3 years ago

3 0

Graph a... you go down on the y axis 3, and then using the rise over run method, you go up 3, over 4

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4/28 - [10 + (3 + 1) x 2]]

Sholpan [36]

Answer:

$\frac{4}{28}-\left(10+\left(3+1\right)x\cdot \:2\right)=-8x-\frac{69}{7}$

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3 years ago

ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -

TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

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3 years ago

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot? 4 StartRoot 2 EndRoot 4 StartRoot 2 EndRoot i

Sveta_85 [38]

Adding $\sqrt{-2}\,\,and\,\,\sqrt{-18}$ we get $4\sqrt{2i}$

Option C 4 StartRoot 2 EndRoot i is correct.

Step-by-step explanation:

We need to find the sum of: $\sqrt{-2}\,\,and\,\,\sqrt{-18}$

Finding sum:

$\sqrt{-2}+\sqrt{-18}$

$\sqrt{-2}$ can be written as $\sqrt{2}i$

$\sqrt{-18}$ can be written as $\sqrt{18}i$

We know 18 = 2x3x3 = 2x3^2 so,

$\sqrt{2i}+\sqrt{2\times 3^2}i$

$\sqrt{2i}+3\sqrt{2}i$

Adding like terms:

$4\sqrt{2i}$

So, adding $\sqrt{-2}\,\,and\,\,\sqrt{-18}$ we get $4\sqrt{2i}$

Option C 4 StartRoot 2 EndRoot i is correct.

Keywords: Square root expressions

Learn more about Square root expressions at:

#learnwithBrainly

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3 years ago

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Answer

It would be 1

Step-by-step explanation:

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