My friend sets out walking at a speed of 3 miles per hour. I set out behind her 5 minutes later at 4 miles per hour.

Find the value of x in the triangle shown below. 9 12

leva [86]

The answer would be 14

7 0

2 years ago

Read 2 more answers

Find the maximum value of the function

romanna [79]

The maximum value of the function is 5/4.

6 0

3 years ago

Read 2 more answers

In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.

lesya692 [45]

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor k from ΔBAC to ΔDEF:

$\displaystyle 5 k = 4$

Solve for the scale factor k:

$\displaystyle k = \frac{4}{5}$

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

$\displaystyle \Delta EDF = \frac{16}{25}\left(15\right) = 9.6\text{ in}^2$

In conclusion, the area of ΔEDF is 9.6 square inches.

5 0

2 years ago

HELP “The vertical supports in this truss bridge are built so that

ElenaW [278]

Answer:

The statement that is not true is;

c) m∠ABO = m∠ODC

Step-by-step explanation:

With the assumption that the lengths AO, and OD are equal, we have that in ΔABO and ΔOCD, the following sides are corresponding sides;

Segment AO on ΔABO is a corresponding side to segment OD on ΔOCD

Vertices B and C on ΔABO and ΔOCD are corresponding vertices

Therefore;

Segments AB and OB on ΔABO are corresponding sides to segments OC and OD on ΔOCD respectively

Therefore, ∠ABO on ΔABO is the corresponding angle to ∠OCD on ΔOCD

Given that ΔABO ≅ ΔOCD, we have that ∠ABO ≅ ∠OCD

Therefore;

m∠ABO = m∠OCD by definition of congruency

5 0

2 years ago

On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).

Valentin [98]

Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

Use distance formula.

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

~ Put all values.

$d = \sqrt{ {( - 4 + 4)}^{2} + ( { - 10 + 4)}^{2} }$

~ Simplify it.

$d = \sqrt{ {0}^{2} + ( { - 6)}^{2} }$

$d = \sqrt{36}$

Therefore, distance between the points is 6 units.

Hope it helps...

6 0

3 years ago