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natulia [17]
3 years ago
13

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units.

Mathematics
2 answers:
Archy [21]3 years ago
7 0

Answer:

B. 14.8 units3

Step-by-step explanation:

You need to use the following formula:

Where "B" is the area of its base and "h" is the height.

According to the data given in the exercise, you know that:

Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.

Lelechka [254]3 years ago
6 0

Answer: Second option.

Step-by-step explanation:

You need to use the following formula:

V=\frac{1}{3}Bh

Where "B" is the area of its base and "h" is the height.

According to the data given in the exercise, you know that:

B=7.4 units^2\\\\h=6\ units

Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.

Then, you get:

V=\frac{1}{3}(7.4 units^2)(6\ units)\\\\V=14.8\ units^3

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2 years ago
Which would be the best method to use to solve the following equations? Explain your reasoning.
o-na [289]

A. square root property

3x^2-192=0\\x^2-66=0\\x^2=66\\x= -\sqrt{66} or \sqrt{66}

it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format

B. factorising

x^2-x-6=0\\x^2+2x-3x-6=0\\(x+2)(x-3)=0\\x+2=0  and  x-3=0\\x= -2 \\x= 3

i just felt like this was easier to factorise than the other 2 options left

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