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____ [38]
2 years ago
14

Brad has eight more nickels than quarters. Altogether he has $6.10. how many of each does he have

Mathematics
1 answer:
wlad13 [49]2 years ago
7 0

Brad have 19 quarters and 27 nickels.

Step-by-step explanation:

Given,

Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents

One quarter = 25 cents

One nickel = 5 cents

Let,

x represent the number of quarters.

y represent the number of nickels.

According to given statement;

25x+5y=610     Eqn 1

y = x+8              Eqn 2

Putting value of y from Eqn 1 in Eqn 2

25x+5(x+8)=610\\25x+5x+40=610\\30x=610-40\\30x=570

Dividing both sides by 30

\frac{30x}{30}=\frac{570}{30}\\x=19

Putting x=19 in Eqn 2

y=19+8\\y=27

Brad have 19 quarters and 27 nickels.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/9369548
  • brainly.com/question/9328925

#LearnwithBrainly

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Add 2 to both sides

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Joey puts 25% of his allowance into savings each week. If last week he put 10$ in savings, what was his allowance last week?​
GrogVix [38]

Answer:

$40

Step-by-step explanation:

25% is 1/4.

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7 0
2 years ago
Larry Mitchell invested part of his $36,000 advance at 7% annual simple interest and the rest at 2% annual simple interest. If h
alisha [4.7K]

The amount invested at each rate

Investment at 7% = $25000

Investment at 2%  = $11,000

<h3>What is investment?</h3>

Investment definition is an asset acquired or invested in to build wealth and save money from the hard earned income or appreciation.

Given:

Larry Mitchell invested = $36,000 at 7% annual simple interest

the rest at 2% annual simple interest.

Total investment = 36000

let the investment at 7% is x

then, invested at 2% = 36000 - x

Total interest earned = $1,970

Simple interest = principal * rate * time

Investment at 4%:

(x * 0.07) + [(36000 - x) * 0.02] = 1970

0.07x + 720 - 0.02x= 1970

0.05x = 1970-720

0.05x = 1250

x= 25000

Hence,

Investment at 7% = $25000

Investment at 2% = $36,000 - $25000 = $11,000

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7 0
1 year ago
A quadratic equation function f(x)=ax^2 passes through (0,0) and (5,5). write an equation for this function
Alex
Equation: f(x)=(1/5)x^2 or f(x)=(0.2)x^2

Check:
f(0)=(1/5)(0)^2
f(0)=(1/5)(0)
f(0)=0✓
f(5)=(1/5)(5)^2
f(5)=(1/5)(25)
f(5)=5✓
6 0
3 years ago
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