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Neko [114]
3 years ago
14

Identify the x-intercept and y-intercept of the equation below.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
Divide by 21 to put the equation in intercept form.
  x/(21/9) + y/(-21/7) = 1
  x/(7/3) + y/(-3) = 1

The x-intercept is (7/3, 0)
The y-intercept is (0, -3)

The 3rd choice is appropriate.

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0.2(x + 1) + 0.5x = -0.3(x - 4)?
andreyandreev [35.5K]

Answer:

x=1.....................

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3 years ago
The measure of an angle is 51 degrees
ki77a [65]
Supplementary angle = 180

180 - 51 = x

x = 129

C) 129 degrees is your answer

hope this helps
5 0
3 years ago
PLS HELP ME QUICK BRAINLIEST +15 POINTS!!!!!
Ipatiy [6.2K]

Answer:

3/4

Step-by-step explanation:

The mean of a data set is synonymous with the average. To find the mean, add up all the values in the data set and then divide by the number of elements.

From the table, there is 12 values. Thus, add up all the 12 values and then divide by 12:

\bar x=\frac{(-3)+4+8+(-1)+(-4)+(-2)+0+2+5+2+(-3)+1}{12}

Simplify:

\bar x=\frac{9}{12}

Reduce:

\bar x=3/4

Therefore, the mean of the data set is 3/4.

For the data set, this means that the average person guesses the temperature too high by about 3/4°F.

(Note: the symbol of x with a bar over it denotes the mean of a set)

7 0
3 years ago
The discount on a new computer was $150. This was a discount of 23 %. Step 1 of 3: What was the original selling price of the co
disa [49]
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3 0
3 years ago
Read 2 more answers
a meal at a restaurant cost $49.28. If the customers leave $8.23 for to determine the tip rate to the nearest whole percent. Wha
Monica [59]
Now, if the customers left 8.23 extra, based on a percentage of the cost of the meal, namely, the 8.23 is a percent of 49.28, then

if we take 49.28 to be the 100%, how much of a percentage is 8.23?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
49.28&100\\
8.23&t
\end{array}\implies \cfrac{49.28}{8.23}=\cfrac{100}{t}\implies t=\cfrac{8.23\cdot 100}{49.28}
8 0
3 years ago
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