All categories

2 years ago

What is the slope of this line? 23 13 −13 −23

Mathematics

2 answers:

Verizon [17]2 years ago

6 0

Points

(0, -3) and (-3, -5)

(y - yo) = m.(x - xo)

(-5 - (-3)) = m.(-3 - 0)

(-5 + 3) = -3m

-2 = -3m

m = -2/-3

m = 2/3

tamaranim1 [39]2 years ago

5 0

Check the picture below.

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{9}-\underset{x_1}{(-3)}}}\implies \cfrac{3+5}{9+3}\implies \cfrac{8}{12}\implies \cfrac{2}{3}$

You might be interested in

How many full 4 2/3 in. Sheets can be cut from 22 1/6 in. Stick

Stolb23 [73]

Answer:

Step-by-step explanation:

Because i divided 4 2/3 by 22 1/6 = 4.75 and for full sheets it would be 4

Hope This Helped

5 0

1 year ago

The math club is sponsoring a bake sale.If their goal is to raise at least $200,how many pies must they sell at $4.00 each in or

Tems11 [23]

The math club must sell 50 pies in order to reach the goal of 200 dollars

4 0

3 years ago

Ava deposited $14 in a savings account that earns 2.7% simple interest. What would the graph look like?

katen-ka-za [31]

Deposited amount = $14.

Rate of interest = 2.7%

In decimals 2.7 could be written by dividing 2.7 by 100, we get

0.027.

Interest earned each year = 2.7% of $14 = 0.027*14 = $0.378.

We can make a table to balance by after each year.

First year balance: First year interest + Deposited amount = 0.378 +14 = $14.378.

Second year balance: Second year interest + Deposited amount = 2*0.378 +14 = 0.756+ 14 = $14.756.

Third year balance: Third year interest + Deposited amount = 3*0.378 +14 = 1.134+ 14 = $15.134.

We get four coordinates to graph A(0,14), B(1, 14.378) , C(2, 14.756) and D(3, 15.134).

Plotting those coordinates of the points A, B, C and D on the graph.

8 0

3 years ago

A baker recorded the number of batches of

azamat

Answer:

B. The lower extreme increased.

Step-by-step explanation:

From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.

The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.

The lower extreme isn't affected as the obtained value isn't below 5.

The median value will Increase and the upper quartile value will also increase. Once the upper quartile value increases, the interquartile range will also increase

6 0

2 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

2 years ago

Read 2 more answers