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3 years ago

14

The green line below

2 answers:

Salsk061 [2.6K]3 years ago

7 0

Answer:

B, C, D, E

Step-by-step explanation:

It is diagonal, and so neither perpendicular nor parallel to either axis (the axes are the two bold lines with markings).

It does cross the axes.

The xy plane is the whole thing, so the line is certainly <em>in</em> them.

It does cross the origin, the point where the axes intersect.

kenny6666 [7]3 years ago

3 0

Answer:

B, C, D, & E

Step-by-step explanation:

All lines intersect the x axis and y axis so we know B and D are correct. All graphs are in the xy plane unless i ( $\sqrt{-1}$ ) is involved, or C. It crosses the center (origin) of the entire plane so it crosses the origin, or E.

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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em> $_{i}$ , of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

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3 years ago

Find the ending balance $35,600 at 9% for 2 years

tino4ka555 [31]

Answer:

42,008

Step-by-step explanation:

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Citrus2011 [14]

Answer:

y= -1/4 x + 4

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3 years ago

A wheel has a radius of 15 cm. Approximately how far does it travel in 4 revolutions?

ArbitrLikvidat [17]

Radius is 15 cm
Circumference = 2 pi r
C = 2 x 3.14 x 15cm
C = 94.2 cm
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7 0

3 years ago

Need help immediately

vekshin1

The answer is 6*square rooted*2

3 0

3 years ago