Through what angle does the bowling ball turn as it travels the length of the lane

A total of 75 cookies and cakes were donated for a bake sale to raise money for the football team. There were four times as many

MArishka [77]

Answer:

60

Step-by-step explanation:

15*4 = 60

15+60= 75

6 0

2 years ago

Read 2 more answers

2. Solve for y. A 10.5 B 9 C 13.5 D 12

Vera_Pavlovna [14]

It’s A
Because if you subtract 12 from 96 you’ll get 8y=84 then divide both sides by 8 you get 21/2 simplify and get 10.5 or 10 1/2

5 0

2 years ago

You take a quiz with 6 multiple choice questions. After you studied your estimated that you would have about an 80 % chance of g

Arada [10]

Answer:

1.15%

Step-by-step explanation:

To get the probability of m independent events you multiply the individual probability of each event. In this case we have m independent events, each one with the same probability, therefore:

$p^{m}$

$0.8^{20} = 1.15\%$

This is a particlar scenario of binomial distribution problem. So the binomial distribution questions are about the number of success of m independent events, where every individual event has the same p probability. In the question we have 20 events and each event has a probability of 80%. The binomial distribution formula is:

$\binom{n}{k} * p^{k} * (1-p)^{n-k}$

n is the number of events

k is the number of success

p is the probability of each individual event

$\binom{n}{k}$ is the binomial coefficient

the binomial coefficient allows to find the subsets of k elements in a set of n elements. In this case there is only one subset possible since the only way to get 20 of 20 correct questions is to getting right all questions (for getting 19 of 20 questions there are many ways, for example getting the first question wrong and all the other questions right, or getting second questions wrong and all the other questions right, etc).

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

therefore, for this questions we have:

$\frac{20!}{20!(20-20)!} * 0.8^{20} * (1-0.8)^{0} = 1.15\%$

4 0

2 years ago

SOLVE USING ELIMINATION *20 POINTS*

V125BC [204]

1. No answer ( may be due to incorrect question)

2. x = -3

y = 4

3. x= 4

y = 2

4.x = -63/40

y= -19/20

Step 1

Multiply equation 1 by the coefficient of x in equation 2

Multiply equation 2 by the coefficient of x I'm equation 1

(after completing this step you will derive equation 3 and 4 )

Step 2

Subtract equation 4 from equation 3

Step 3

Divide both sides of the equation by the coefficient of y

Step 4

substitute your value for y in equation 1 or 2

(after this you will derive the values of x)

Note : This method is for the Elimination of x

I hope it helps

5 0

3 years ago

Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.

adoni [48]

again, let's assume daily compounding means 365 days per year.

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}$

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}$

$A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}$

what's their difference? well

$\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}$

7 0

1 year ago