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Wittaler [7]
3 years ago
12

Let W be the event that a randomly chosen person works for the city government. Let V be the event that a randomly chosen person

will vote in the election. Place the correct event in each response box below to show: Given that the person works for the city government, the probability that a randomly chosen person has will vote in the election. Provide your answer below:
Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

We can express that probability as P(V | W), the probability of V given W.

Step-by-step explanation:

We know that the chosen person works for the goverment, so we have to assume W as hypothesis. Therefore, in order to calculate the probability of that person voting on the election, event noted by V,  we have to <em>condition</em> V to the event W. As a result, we want the probability of V given W, which can be written as P(V | W), and it can be calculated using this formula

P(V | W) = P(V \cap W) / P(W)

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Dima020 [189]

Answer:GH = 5

Step-by-step explanation:

GJ = GH + HI + IJ

It is given that GH = IJ

Also, it can be seen that HJ = HI + IJ

We want to determine GH.

From the information given,

HJ = 7 and HI = 2. This means that

7 = 2 + IJ

Subtracting 2 from the left hand side and the right hand side of the equation, it becomes

IJ + 2 - 2 = 7 - 2

IJ = 5

Since GH = IJ, then it means that

GH = 5

5 0
4 years ago
PLEASE HELP 99 POINTS
statuscvo [17]
Presumably, h(x)=3(5)^x. In that case,

(A)
The average rate of change over the interval 0\le x\le1 is

\dfrac{h(1)-h(0)}{1-0}=\dfrac{15-3}1=12

and over 2\le x\le3, it's

\dfrac{h(3)-h(2)}{3-2}=\dfrac{375-75}1=300

(B)
\dfrac{300}{12}=25, i.e. the average rate of change over the second interval is 25 times higher. That's to be expected; 3(5)^x is an exponential function. As x gets larger, the rate of change of h(x) gets larger too.
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3 years ago
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erastova [34]

Answer:

A

Step-by-step explanation:

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Answer:27000000

Step-by-step explanation:

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kondaur [170]
The length of the side joining points (-3, -1) and (1, 3) is given by

l= \sqrt{(1+3)^2+(3+1)^2}  \\  \\ = \sqrt{4^2+4^2} = \sqrt{16+16}  \\  \\ = \sqrt{32}

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w= \sqrt{(3-1)^2+(1-3)^2} \\ \\ = \sqrt{2^2+(-2)^2} = \sqrt{4+4} \\ \\ = \sqrt{8}

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Thus, the area of the given rectangle is given by

Area=l\times w \\  \\ = \sqrt{32} \times \sqrt{8}  \\  \\ = \sqrt{32\times8} = \sqrt{256}  \\  \\ =\bold{16} \ units^2
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