Answer:
Power = 21[W]
Explanation:
Initial data:
F = 35[N]
d = 18[m]
In order to solve this problem we must remember the definition of work, which tells us that it is equal to the product of a force for a distance.
Therefore:
Work = W = F*d = 35*18 = 630 [J]
And power is defined as the amount of work performed in a time interval.
Power = Work / time
Time = t = 30[s]
Power = 630/30
Power = 21 [W]
Answer:
See below
Explanation:
An object at rest tends to stay at rest unless acted on by a force
The distance between two objects is doubled, the force between them drops to a quarter (1/22<span> or 1/4). If the distance is increased ten times, the force between the two objects decreases to a hundredth of what it was (1/10</span>2<span> or 1/100).</span>
I would read Choice #2 to him, enunciating clearly.
Answer:
Explanation:
Mass of a hockey puck, m = 0.17 kg
Force exerted by the hockey puck, F' = 35 N
The force of friction, f = 2.7 N
We need to find the acceleration of the hockey puck.
Net force, F=F'-f
F=35-2.7
F=32.3 N
Now, using second law of motion,
F = ma
a is the acceleration of the hockey puck
So, the acceleration of the hockey puck is .