1) First of all, let's find the resistance of the wire by using Ohm's law:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
by using the following relationship:
Where A is the cross-sectional area of the wire and L its length.
We already have its length
, while we need to calculate the area A starting from the radius:
And now we can find the resistivity:
Answer:
By energy efficient, if you mean LED, no the lamp will not flow like normal. If the bulb is still an incandescent but slightly lower wattage, it will take a little longer to get going. Lava lamps require heat and light for the effect to work.
Answer:
The mass is inversely proportional to the acceleration so the acceleration a1 is twice that acceleration a2
Explanation:
The force of friction and the kinetic force make the law of mass in moving so
The forces are the same however at the moment to determinate the acceleration
are constant because they make the same motion however the difference of mass make the acceleration difference
Answer:
(a) 83475 MW
(b) 85.8 %
Explanation:
Output power = 716 MW = 716 x 10^6 W
Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3
mass of water, m = Volume x density = 1.35 x 10^8 x 10^-3 x 1000
= 1.35 x 10^8 kg
Time, t = 1 hr = 3600 second
T1 = 25.4° C, T2 = 30.7° C
Specific heat of water, c = 4200 J/kg°C
(a) Total energy, Q = m x c x ΔT
Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J
Power = Energy / time
Power input =
Power input = 83475 MW
(b) The efficiency of the plant is defined as the ratio of output power to the input power.
Thus, the efficiency is 85.8 %.
Given :
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.
To Find :
The velocity of the center of mass of these two particles.
Solution :
Speed of mass m, .
Speed of mass 2m , .
Speed of center of mass is given by :
Hence, this is the required solution.