Answer:
a) 17.33 V/m
b) 6308 m/s
Explanation:
We start by using equation of motion
s = ut + 1/2at², where
s = 1.2 cm = 0.012 m
u = 0 m/s
t = 3.8*10^-6 s, so that
0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²
0.012 = 0.5 * a * 1.444*10^-11
a = 0.012 / 7.22*10^-12
a = 1.66*10^9 m/s²
If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where
E = electric field
m = mass of proton
a = acceleration
q = charge of proton
E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19
E = 2.77*10^-18 / 1.6*10^-19
E = 17.33 V/m
Final speed of the proton can be gotten by using
v = u + at
v = 0 + 1.66*10^9 * 3.8*10^-6
v = 6308 m/s
If Ross takes two months off from training, his fitness level will reduce in comparison to what it was two months ago.
- In as little as 3–4 weeks after beginning strength training, Ross will probably experience weight increase, energy loss, diminished balance, diminished strength (making it tougher to carry out daily tasks), and overall fewer fitness levels.
- Many people mistakenly believe they lose muscle mass far more quickly than they actually do because their muscles' ability to store water and glycogen is declining.
- A decrease in strength and muscle mass, with beginners experiencing a smaller decline in strength than experienced lifters.
- Ross will experience Increased VO2 Max from exercise. VO2 Max is almost completely lost in people who train at lower intensities.
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Answer: in the smaller/ thinner pieces.
Answer:
V(average)=6.37 V
Explanation:
Given Data
Peak Voltage=10V
Frequency=10 kHZ
To Find
Average Voltage
Solution
For this first we need to find Voltage peak to peak
So
Voltage (peak to peak)= 2× voltage peak
Voltage (peak to peak)= 2×10
Voltage (peak to peak)= 20 V
Now from Voltage (peak to peak) formula we can find the Average Voltage
So
Voltage (peak to peak)=π×V(average)
V(average)=Voltage (peak to peak)/π
V(average)=20/3.14
V(average)=6.37 V
