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3 years ago

4 times the sum of a number and -6 equaled 10. what's the #?

Mathematics

1 answer:

kakasveta [241]3 years ago

5 0

The answer is 8.5. you simply take the worded equation above and turn it into a math problem (a+-6) x 4

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If the length of an arc intercepted by a central angle of 1.25 radians is 32 inches, which proportion could be used to find the

Softa [21]

Answer:

Option 4: 1.25/2π = 32/2πr

Step-by-step explanation:

Arc length = (theta/2pi) × 2pi × r

32 = (1.25/2pi) × 2pi × r

1.25/2pi = 32/(2pi × r)

8 0

3 years ago

Find the value of x.

Jobisdone [24]

X=180-125-39=16 degrees

6 0

3 years ago

A cylindrical can contains an unknown number of golf balls. The can has a height of 10 inches and a volume of 15.625 Pi inches c

AlladinOne [14]

20 golf balls can fit in the can.

<u>Step-by-step explanation:</u>

Given:

Height (h) = 10 Inches

Volume of 15.625 Pi inches cube.

To Find:

How many balls can be filled in that can.

Solution:

Diameter of the golf ball [as per standard value] = 1.68 in

Radius of the golf ball = $\frac{1.68}{2} = 0.84 in$

Volume of the golf ball = $\frac{4\pi r^3}{3}$

= $\frac{4\pi (0.84)^3}{3}$

= $2.5 (or) 0.79 \pi inches$

Volume of the can = $15.625\pi in^3$

Now we have to divide the volume of the can by the volume of the golf ball, we will get = $\frac{15.625 \pi }{0.79\pi } = 19.7$ balls

Thus we can conclude that approximately 20 balls can be filled in that can.

7 0

4 years ago

HELP PLEASEEEE it’s due in 10 minutes

lana [24]

Answer:

24.187

Step-by-step explanation:

7 0

3 years ago

HELP

babymother [125]

It's a isosceles right angled triangle

LJ=17
KL=10

$\\ \sf{:}\Rrightarrow JK^2=17^2+10^2$

$\\ \sf{:}\Rrightarrow JK^2=289+100$

$\\ \sf{:}\Rrightarrow JK^2=389$

$\\ \sf{:}\Rrightarrow JK=19.72$

4 0

3 years ago