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denpristay [2]
3 years ago
8

C = 5(F -32)/ 9; for F

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

32+9C/5

Step-by-step explanation:

First you must follow PEMDAS, the order of operations. So you mutiply 9 by both sides to get 9C =5(F - 32) then you must divide by 5, to get

9C/5=F-32 and lastly you must add 32 to both sides to cancel out the 32 leaving you with 32+ 9C/5

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My Prime factors are 2,3, and 5, and I am a number between 58 and 68. What number am I?
abruzzese [7]
Well, because the number has to be a multiple of 5, it must be either 60 or 65. Then, you see that only 60 fits the description because it is divisible by both 2 and 3 while 65 is divisible evenly by neither
5 0
3 years ago
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What is the answer to -10x-1=11-9x
Harman [31]
-10x-1 = 11 -9x
+10x +10x
-1 = 11 + x
-11 -11
-12 = x

x= -12
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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 23 in. by 13 in. by
faltersainse [42]

Answer:

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is 361.19 in^3.

Step-by-step explanation:

Given that the dimensions of a cardboard is 23 in by 13 in.

Let the side of the square be x in.

Then the length of the box= (23-2x) in

and the width of the box =(13-2x) in

and height = x in.

The volume of the box is = length ×width × height

                                         =[(23-2x)(13-2x)x] in^3

                                         =(299x-72x² +4x^3) in^3

∴V=299x-72x² +4x³

Differentiating with respect x

V'= 299-144x+12x²

Again differentiating with respect x

V''= -144+24x

To find the dimensions, we set V'=0

∴299-144x+12x²=0

Applying Sridharacharya formula that is the solution of a quadratic equation ax²+bx+c is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here a=12, b=-144 , c=299

\therefore x=\frac{-(-144)\pm\sqrt{(-144)^2-4.12.299}}{2.12}

\Rightarrow x= 9.33, 2.67

If  we take x=9.33 in, then the width of the box [13-(2×9.33)] will negative.

∴x = 2.67 in

If at x = 2.67, V''<0 , then the volume of the box will be maximum or V''>0 then volume of the box will be minimum.

V''|_{x=2.67}=-144+(24\times 2.67)=-79.92

Therefore  at x = 2.67, the volume of the box maximum.

The length of the box =[23-(2×2.67)] in

                                    =17.66 in

The width of the box =[13-(2×2.67)] in

                                  =7.66 in

The height of the box= 2.67 in

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is =(17.66×7.66×2.67) in^3

                                                            =361.19 in^3

8 0
3 years ago
8^x=2 write down the value of x
e-lub [12.9K]

Answer:

x = \frac{1}{3}

Step-by-step explanation:

Using the rule of exponents

a^m^{n} = a^{mn}

Note that 8 = 2³ and 2 = 2^{1}, then

(2^3)^{x} = 2^{1}, that is

2^{3x} = 2^{1}

Since the bases on both sides are equal, equate the exponents

3x = 1 ( divide both sides by 3 )

x = \frac{1}{3}

4 0
3 years ago
How do I do angles of triangles​
BigorU [14]

Answer:

What kind of angles?

Step-by-step explanation:

What is your question?

7 0
3 years ago
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