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2 years ago

C = 5(F -32)/ 9; for F

Mathematics

1 answer:

ololo11 [35]2 years ago

3 0

Answer:

32+9C/5

Step-by-step explanation:

First you must follow PEMDAS, the order of operations. So you mutiply 9 by both sides to get 9C =5(F - 32) then you must divide by 5, to get

9C/5=F-32 and lastly you must add 32 to both sides to cancel out the 32 leaving you with 32+ 9C/5

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2 years ago

Read 2 more answers

The difference of two numbers is 33. The sum of the first number and four times the second number is -2. What is the larger of t

defon

Answer:

The larger of the two is 44.67

Step-by-step explanation:

let the first number=x

let the second number=y

We can derive a system of equations using the mathematical statements

Their sum is 33:

x+y=33( call this equation 1)

Sum of first number and four times the second is -2:

x+4y=-2(call this equation 2)

Since the integer coefficients of x in both equations are the same we can quickly subtract one from the other to eliminate it

For this explanation, I choose to subtract equation 1 from 2

(x+4y=-2)-(x+y=33)=3y=-35

y=-35/3

Now plug in the value of y into any equation for that of x. Say we plug into equation 1

x+(-35/3)=33

x-35/3=33( multiply through by 3)

3x-35=99

3x=99+35

3x=134

x=134/3

Therefore,x=134/3 or 44.67 and y=-35/3 or -11.67

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2 years ago

Write 19/50 as a decimal and round to the hundredths place

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Answer:

0.38

Step-by-step explanation:

Divide 19 by 50.

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2 years ago

How do I find the measures of the indicated angle that makes lines U and V parallel

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Answer:

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Step-by-step explanation:

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2 years ago

B: Alex is 12 years older than George.

UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

$g+a+c=68 \ \ \ \ equation 1$

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

$a =g+12 \ \ \ \ equation \ 2$

Now Given:

Carl is three times older than Alex.

$c=3a$

But $a =g+12$

So we get;

$c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3$

Now Substituting equation 2 and equation 3 in equation 1 we get;

$g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68$

Subtracting both side by 48 using subtraction property of equality we get;

$5g+48-48=68-48\\\\5g=20$

Now Dividing both side by 5 using Division property of equality we get;

$\frac{5g}{5}=\frac{20}{5}\\\\g =4$

Hence George age $g = 4 \ years$

Now Alex age $a=g+12 = 4+12 =16\ years$

Also Carl's age $c=3g+36=3\times 4+36 =12+36 =48\ years$

Now we need to find the ratio of George age to Carl's age.

$\frac{g}{c}=\frac{4}{48} = \frac{1}{12}$

Hence the ratio of George age to Carl's age is 1:12.

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2 years ago