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garri49 [273]
3 years ago
15

1) A projectile is thrown upward so that its distance above the ground after t seconds is

Mathematics
1 answer:
leonid [27]3 years ago
4 0

Answer:

After 22 seconds the projectile reach its maximum height of 4,840 units

Step-by-step explanation:

we have

h(t)=-10t^{2}+440t

This is a vertical parabola downward (because the leading coefficient is negative)

The vertex is a maximum

Find out the coordinates of the vertex

Convert the quadratic equation in vertex form

Factor -10

h(t)=-10(t^{2}-44t)

Complete the square

h(t)=-10(t^{2}-44t+22^2)+(10)(22^2)

h(t)=-10(t^{2}-44t+22^2)+4,840

Rewrite as perfect squares

h(t)=-10(t-22)^{2}+4,840

The vertex is the point (22,4,840)

therefore

After 22 seconds the projectile reach its maximum height of 4,840 units

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