Consider the offered option:
if suppose, that unknown side is '?', then
2*(3x-3)+2*'?'=10x+6;
6x-6+2*'?'=10x+6;
2*'?'=4x+12;
'?'=2x+6
Answer: 2x+6
Answer:
x = 9
Step-by-step explanation:
Step 1: Write equation
x + 8 = 17
Step 2: Solve for <em>x</em>
- Subtract 8 on both sides: x = 9
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
9 + 8 = 17
17 = 17
Answer:
o lines
Step-by-step explanation:
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,

As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
To solve for c, you need to get c onto one side of the equation, or make it c=__. So what I would do first is subtract a/b from both sides
a/b + c = d/c
-a/b
a/b - a/b + c = d/c - a/b
c = d/c-a/b