PLEASE HELP ME I BEGGING YOU PLEASE HELP I DO ANYTHING JUST HELP
1 answer:
You might be interested in
Answer:
y = 1.
Step-by-step explanation:
f(x) = x^2 + 1
We know that:
replacing the function, we get:
Now we can simplify this to:
and solving the quotient, we get:
then f'(x) = 2*x
And we want the equation for the tangent line at (0, 1)
The slope of that line will be:
f'(0) = 2*0 = 0
So this is a horizontal line, of the type y = a
And we know that this line must pass through the point (0, 1)
so we must have y = 1.
Then the equation of the tangent line to f(x) at the point (0, 1) is:
y = 1.