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3 years ago

Is X=3 calculate the value of X3+X btw the 3 is a small three

2 answers:

7 0

I think the answer is 12 but I don't know what you mean by "small 3." Tell me if my answer is wrong and I will try to fix it.

Naddik [55]3 years ago

3 0

The only 'small number' that I know that would affect the answer is an exponent that looks like ³ so the problem would be x³+x

remember that x³=x times x times x
if x=3 then
3³+3=27+3=30

You might be interested in

I really need help with this ASAP

Alexandra [31]

Answer:

No. of boxes = 10

Oranges per box = 56

Total no. of oranges = 56*10=560

No. of bad oranges = 560/40= 14

(i) Probability of bad orange = 14/560 = 1/40

(ii) no of oranges expected to be bad = 14 ( found above)

Hope it helps.............. :)

7 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

The 10 participants in an experiment had the following reaction times (in milliseconds). 242, 485, 485, 489, 497, 498, 500, 507,

Karolina [17]

Answer:

The outliers are 242 and 875

Step-by-step explanation:

Their numbers are far more away than the other numbers if you had it on a number line. Most of the numbers range from 480-510 (estimation of the range, sorry hehe), so the numbers that seem very far (almost excluded, I guess) would be the ones that are considered the outliers.

242 and 875 are over 100 spaces away from the other numbers, meanwhile 485,485,489,497,498,500,507,509 have shorter spaces in between.

I hope this helped! (Sorry, if it sounds confusing)

5 0

2 years ago

Minimon común numtiplo de 4800 1350 y 2646

marishachu [46]

Answer:

LCM of (4800, 1350, 2646) = 2116800

Step-by-step explanation:

Factorización prima de los números:

4800 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5

1350 = 2 × 3 × 3 × 3 × 5 × 5

2646 = 2 × 3 × 3 × 3 × 7 × 7

MCM (4800, 1350, 2646)

2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5 × 7 × 7

2116800

MCM de (4800, 1350, 2646) = 2116800

3 0

3 years ago

In a survey, one out of five people named blue as their favorite color. Three out of ten named red. If 1,100 people were include

bagirrra123 [75]

1/5 = x/1100

5x = 1100
x = 1100 ÷ 5
x = 220

So 220 people named blue as fav.

3/10 = x/1100

3x = 1100
x = 1100 ÷ 3
x = 366.6666.... = 367

So 367 people chose red

8 0

4 years ago