Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:
(4n + 1)²(4n - 1)²
= [(4n + 1)(4n - 1)]²
= (16n² - 1)²
= 16².n².n² - 2.16.n² + 1
= 8n²(32n² - 4) + 1
can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8
=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.
Step-by-step explanation:
They definitely can be positive they can be negative and they can have an absolute value but I would choose they both can be positive and negative
<h2>INVERSE VARIATION</h2>
<em>E</em><em>Q</em><em>U</em><em>A</em><em>T</em><em>I</em><em>O</em><em>N</em><em>:</em><em> </em><em> </em><em> </em><em> </em>

<em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em>
First, find the constant of variation <em>k</em> using the formula k=xy.



<em>–</em><em>–––––––</em>
Then, find <em>y</em> if <em>x</em> is equal to four using the formula y=184/x.



<em>F</em><em>i</em><em>n</em><em>a</em><em>l</em><em> </em><em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em>
<h2>y = 46</h2>
Answer:
Step-by-step explanation:


Answer:
its c)
Step-by-step explanation:
just looked it up