Hm.. That's a hard one is the answer..10??
Answer:
log9
Step-by-step explanation:
hello :
note : a>0 and b>0
1) log(ab) = loga+logb
2) loga^n = nloga.....n in N
log(9x^5) + 5 log (1/x) = log(9x^5) + log (1/x)^5 = log((9x^5) (1/x)^5)
= log(9x^5)/(x^5)) = log9 because : (1/x)^5 = 1/x^5
22.5 miles
You would create a proportion based on the given information, then cross multiply and solve for the number of miles 1 gallon of gas can go.
Answer:
I think 2600 passwords are possible