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2 years ago

A. $5.25 B. $6.15 C. $7.00 D. $9.30

Mathematics

2 answers:

Ne4ueva [31]2 years ago

3 0

Answer:

$6.15

Step-by-step explanation:

1.80/2=0.9

3.50*1.5=5.25

1.75+0.9=6.15

Dvinal [7]2 years ago

3 0

Answer:

B) $6.15

Step-by-step explanation:

It is given that: 1 pound of corn = $1.80

1 pound of green beans = $3.50

You are buying 1/2 a pound of corn, or: 1.80/2 = $0.90

You are also buying 1 1/2 pounds of green beans, or 3.50 x 1.5 = $5.25

Add the two costs to get the total amount:

$5.25 + 0.90 = $6.15

B) $6.15 is your answer.

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In right triangle KLM, KL =14 and angle L=30° and angle M=90°. Find KM. Leave your answer in the simplest radical form.

salantis [7]

Answer:

KM = 7 Units

Step-by-step explanation:

In the given structure ΔKLM

∠KLM = 30° and side KL = 14 and ∠KML = 90°

and we have to find the measurement of KM.

From right angle triangle KLM

Side Sin30° = KM/KL = KM/14

KM = 14×sin30° = 14×1/2 = 7

So the answer is KM = 7 Units

5 0

3 years ago

if a car travels 370.3 miles on 52 liters of gas, how many liters of.gas.will take to go 722 miles.if the car travels at the sam

blsea [12.9K]

Answer:

101.4 liters.

Step-by-step explanation:

First of all we will find mileage of car.

$\text{Mileage of car}=\frac{\text{Total distance traveled}}{\text{Total amount of fuel}}$

$\text{Mileage of car}=\frac{370.3\text{ miles}}{52\text{ liters gas}}$

$\text{Mileage of car}=7.12115\frac{\text{ miles}}{\text{ liters gas}}$

We can see that car travels at the rate of 7.12 miles per liter gas. Now let us find amount of gas needed to travel 722 miles at the same rate.

$\text{Amount of gas needed}=\frac{722}{7.12}$

$\text{Amount of gas needed}=101.388$

Therefore, it will take 101.4 liters of gas to travel 722 miles.

4 0

3 years ago

I need help on 17 and 23 pls

ludmilkaskok [199]

Question # 17 Solution

Answer:

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Step-by-step Explanation:

The given expression

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

And we have to solve for x₁

So,

Lets solve for x₁.

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Multiply both sides by x₂ - x₁

$m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m(x_{2}-x_{1})= (y_{2}-y_{1})$

$mx_{2}-mx_{1}= (y_{2}-y_{1})$

$-mx_{1}= y_{2}-y_{1}-mx_{2}$

Divide both sides by -m

$\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}$

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Therefore, $x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Question # 23 Solution

Answer:

$n= \frac{bx}{-b + x}$

Step-by-step Explanation:

The given expression

$\frac{nx}{b}-x=x$

And we have to solve for n

So,

Let's solve for n.

$\frac{nx}{b}-x=x$

Multiply both sides by b.

$-bn + nx = bx$

Factor out n.

$n(-b + x)= bx$

Divide both sides by -b + x.

$\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}$

$n= \frac{bx}{-b + x}$

Therefore, $n= \frac{bx}{-b + x}$

Keywords: solution, equation

Learn more about the solution of equations from brainly.com/question/12864981

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6 0

3 years ago

Q28. In a sale, the normal price of a book is reduced by 30%. The sale price of the book is £2.80 Work out the normal price of t

lisov135 [29]

Answer:

0.90

Step-by-step explanation:

090. = 0.90

30/2.80

8 0

3 years ago

The quotient of a number and -9 increased by 10 is 11.

andrezito [222]

So the division of a number and -9 or
x/-9

+10=11 or

(x/-9)+10=11
subtract 10 from both sides
x/-9=1
multiply both sides by -9
x=-9

3 0

3 years ago

Read 2 more answers