Question

Devin brought his snail collection to school. He has 10 snails. How could he put them into 2 tanks so two classes could see them? write equations for all the possible ways. One of the ways is given. Explain how you know have found all the ways One of the ways is given. Explain how you know have found all the ways

Answer 1

Answer:

$m + n =10$  

Step-by-step explanation:

Total no. of snails Devin has = 10

We have to divide these into two tanks.

Let m be the number of snails in tank 1 and let n be the number of snails in tanks 2.

There are various ways in which these snails could be divided.

We can define an equation that would help us to divide the snail:

$m + n =10$

Ways in which snail can be divided:

When there is 1 snail in tank 1 and other 9 in tank 2 that is m = 1, n = 9

Other ways could be

m =2, n = 8

m = 3, n= 7

m = 4, n= 6

m = 5, n = 5

m = 6, n = 4

m = 7, n = 3

m = 8, n = 2

m = 9, n = 1

We know we have found all the combinations because there are no other possible combinations for sum to be 10.

Answer 2

Its 10×2 and 10+10 because you're doing multiplication