All categories

3 years ago

What is the distance between 178 and 313 on a number line some one help me

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

7 0

The answer for this is 135

liq [111]3 years ago

7 0

<h2>Answer:</h2>

The distance between 178 and 313 on a number line is: 135

<h2>Step-by-step explanation:</h2>

We know that the distance between two points a and b on a number line is equal to the absolute difference between the two numbers.

i.e. Distance between two numbers = |a-b|

Here we have:

a= 178

and b=313

This means that:

|a-b|=|178-313|=|-135|=135

You might be interested in

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

3 years ago

3. Taylor has a $30.00 gift card that she can

Andrew [12]

7 journals is the answer

4 0

4 years ago

Read 2 more answers

22x – 54 + 5.736x^4 - 2x^2<br> Standard form

Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

4 0

3 years ago

{x|x is an odd integer between -3 and 7}

Mandarinka [93]

Answer:

x={-1,1,3,5}

Step-by-step explanation:

x={-1,1,3,5}

8 0

3 years ago

Find the measure of <2.

n200080 [17]

Answer:

$\displaystyle 90° = m∠2$

Step-by-step explanation:

In every rhombus, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, plus, it measures 90° all around, so with that being said, you have your answer.

I am joyous to assist you anytime.

6 0

3 years ago

What is the distance between 178 and 313 on a number line some one help me​

What is the distance between 178 and 313 on a number line some one help me