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sergejj [24]
3 years ago
13

I need help with this

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
I thin the answer's B, 4/13
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560 divided 70 = 56 tens divided 7 tens=
Verizon [17]

Answer:

80

Step-by-step explanation:

<h2>Hope this helped </h2>
3 0
2 years ago
What is the mean, median, mode, and range of this data set, 2,3,2,4,3,3,3,4,2,3,4,2,4,4,9,3,4,4
slava [35]

Answer:

Mean: 3.5

Median: 3

Mode: 4

Range: 7

Step-by-step explanation:

5 0
3 years ago
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( 2 – 3x – 10 ) ÷ ( x – 5 )​
PtichkaEL [24]

Answer:

7

Step-by-step explanation:

hope helps you

6 0
2 years ago
A diagram of Eric pool as shown below. He plans to fill this pool to a depth of 4ft with a garden hose that flows at 80ft expone
Alex777 [14]
<span>The Volume of a Cylinder  =   </span><span>π <span>• r² • height<span>
</span></span></span>radius = 13.5 feet
volume = PI * 13.5^2 * 4 feet (the problem states it is to be filled to a depth of 4 feet)
volume = PI * 182.25 * 4
volume = <span> <span> <span> 2,290 cubic feet</span></span></span>
The hose delivers 80 <span>cubic feet per hour so it will take:
</span>2,290 / 80 = <span> <span> <span> 28.625 </span> </span> </span> hours
**************************************************************************
The volume of the pool is:
volume = PI * 182.25 * 4.5
= <span> <span> <span> 2,576.</span></span></span>5 cubic feet


6 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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