0.0058 expressed as a percentage is

Which of the following statements are true about WaterSense toilets?

Readme [11.4K]

Answer:

option: (a),(b),(c)

Step-by-step explanation:

WaterSense Toilets use 1.28 gallons per flush or less while still providing equal or superior performance. This is 20 percent less water than the current federal standard of 1.6 gallons per flush.

Hence, option D is incorrect.

it was developed with an aim of replacing an old, leaky toilet that is wasting money and water, installing a WaterSense labeled toilet is a high-performance, water-efficient option worth considering.

" The toilet float is a device that allows water to fill the tank without overflowing " .

Hence, option (a),(b) and (c) are true.

7 0

3 years ago

Read 2 more answers

Enter the equation of the circle described below.<br> Center (0,4), radius V3

Alla [95]

Answer:

The equation is:

$(x - 0)^2 + (y - 4)^2 = 3$

Step-by-step explanation:

The equation of a circle:

$(x - h)^2 + (y - k)^2 = r^2$

(where $(h, k)$ represents the center and $r$ the radius).

-Use the given center and radius for the equation of a circle:

$(x - 0)^2 + (y - 4)^2 = \sqrt{3} ^2$

After, you have the equation of a circle written, simplify the radius by the exponent $2$ :

$(x - 0)^2 + (y - 4)^2 = 3$

So now, you have found the equation of a circle.

8 0

3 years ago

1. A luge race is very dangerous, and a crash can cause serious injuries. The league requires anyone who has a crash to have a t

antiseptic1488 [7]

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$