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slavikrds [6]
3 years ago
13

The number of hours a group of contestants spent preparing for a quiz show are listed below. What is a frequency table that repr

esents the data? 60 25 86 56 45 48 90 75 30 67 90 36 80 15 32 65 61
Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0
So if you look at this you will see that 60 - 67 bar has the highest frequency and
30-67 also has the highest frequency if you look at more data. Turn it sideways and you'll see a stem and leaf plot. A quick way to show frequency without messing with the histogram. Either one will show frequency.

15
25
30 32 36
45 48
56
60 61 65 67
75
80 86
90 90





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20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
Marty drinks 2 cups of water each day. Katie drinks 14 times as much as Marty. How many fluid ounces of water do they drink all
Katena32 [7]
224 ounces.?
Gajhfiambzoandhiam
6 0
3 years ago
Compute 33(0.5) - 6(0.5) - 7/2.
lora16 [44]
Hi there! The answer is 10.

33(0.5) - 6(0.5) -  \frac{7}{2}
We can use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Since we cannot work inside the parenthesis in this question and since we don't have exponents, we can move on to multiplying.
16.5 - 3 -  \frac{7}{2}

Our next step would be subtracting. To make the process of subtracting some easier, I'll first change the fraction into a decimal.
16.5 - 3 - 3.5

Finally subtract.
13.5 - 3.5 = 10

The answer is 10.
~ Hope this helps you!
5 0
3 years ago
Read 2 more answers
What is the answer a factory adds three red drops an two blue drops of coloring to white paint to make each pint of purple paint
Elan Coil [88]

Answer:

Red = 30 drops

Blue = 20 drops

Step-by-step explanation:

The ratio red to blue is 3 : 2

Sum of ratios = 3 + 2 = 5

Required purple paint = 50 gallons

So,

Multiplier = \frac{50}{5} = 10

Now, Red drops = 3×10 = 30

Blue drops = 2×10 = 20


4 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
marishachu [46]

Answer:

Thus, the two root of the given quadratic equation  x^2-6=-x  is 2 and -3 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2-6=-x

This can be written as ,  x^2+x-6=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = 1 , c = -6

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(1)\pm\sqrt{(1)^2-4\cdot 1 \cdot (-6)}}{2 \cdot 1}

\Rightarrow x=\frac{-1\pm\sqrt{25}}{2}

\Rightarrow x=\frac{-1\pm 5}{2}

\Rightarrow x_1=\frac{-1+5}{2} and \Rightarrow x_2=\frac{-1-5}{2}

\Rightarrow x_1=\frac{4}{2} and \Rightarrow x_2=\frac{-6}{2}

\Rightarrow x_1=2 and \Rightarrow x_2=-3

Thus, the two root of the given quadratic equation x^2-6=-x is 2 and -3 .

7 0
3 years ago
Read 2 more answers
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