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2 years ago

13

Sammy is conducting a science experiment where he has to mix 8.25 ounces of vinegar and 4.30 ounces of lemon juice how many ounc

es what he mix altogether

1 answer:

dybincka [34]2 years ago

3 0

8.25 + 4.30

(8 + 4) = 12
(.25 + .30) = .55

12 + .55 = 12.55

The answer is 12.55

When a problem says how many ___ altogether, it tells you to add them together

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Oakland Middle school has 128 6th graders, 121 7th graders and 135 8th graders. If there are 3 teachers per 32 students, how man

zepelin [54]

Answer:

36 Teachers in Total

Step-by-step explanation:

I would use Ratio.

Students: 128 + 121 + 135 = 384 total students

Teachers: Students

3 : 32

36 : 384

384 ÷ 32 = 12

12 x 3 = 36

6 0

2 years ago

The table shows the number of games a chess player won in professional competitions, based on the number of games played.

AfilCa [17]

slope = (25-4)/(30-10)

slope = 21/20

slope =21/20

using point slope form

y-y1 = m(x-x1)

y-4 = 21/20 (x-10)

y = 21/20x -21/2 +4

y = 21/20 x -21/2 +8/2

y = 21/20x -13/2

let x=40

y = 21/20 (40) -13/2

y = 42-13/2

y = 35.5 games

If we round the slope to 1

slope =1

using point slope form

y-y1 = m(x-x1)

y-4 = 1 (x-10)

y = 1x -10 +4

y = x -6

let x=40

y = 40-6

y = 34 games

4 0

3 years ago

At the local nursery, 1/4 of the plants for sale are flowers and another 3/5 of them are bushes. What fraction of the plants for

Hitman42 [59]

Answer:

17/20

Step-by-step explanation:

1/4 +3/5 simplify into:

5/20 + 12/20= 17/20

5 0

1 year ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

2 years ago

4/9 expressed as a percent please help and show work! Please

coldgirl [10]

4/9 as a percent is (about) 44% Work:
First get a decimal by dividing 4/9(4 divided by 9) you get 0.44 repeating
Next, take away the 0. and add a percent sign at the end of 0.44. You get 44%
Truly, the answer is 44.44444...% because the four repeats, but if you round it is simply 44%

7 0

3 years ago

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