Answer:
a = 5
Step-by-step explanation:
Hello, please consider the following.

So, a = 5.
Thank you.
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Each bullet would cost 100/80 = $1.25 if 100 bullets cost $80.
Answer:
he is currently 34
Step-by-step explanation:
x + 6 = 5(x-26)
x + 6 = 5x - 130
+130 +130
x + 136 = 5x
-x -x
136 = 4x
/4 /4
x = 34
You can check your work as well:
34 + 6 = 40
34 - 26 = 8
8 x 5 = 40