By using <span>De Moivre's theorem:
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If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴
![\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bz%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5C%20%28cos%20%5C%20%20%5Cfrac%7B%5Ctheta%20%2B%20360K%7D%7Bn%7D%20%2B%20i%20%5C%20sin%20%5C%20%5Cfrac%7B%5Ctheta%20%2B360k%7D%7Bn%7D%20%29)
k= 0, 1 , 2, ..... , (n-1)
For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
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Part (A) <span>
find the modulus for all of the fourth roots </span>
<span>∴ The modulus of the given complex number = l z l = 81
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∴ The modulus of the fourth root =
Part (b) find the angle for each of the four roots
The angle of the given complex number =

There is four roots and the angle between each root =

The angle of the first root =

The angle of the second root =

The angle of the third root =

The angle of the fourth root =
Part (C): find all of the fourth roots of this
The first root =

The second root =

The third root =

The fourth root =
Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
Answer:
A die is thrown which means that it can land on either 1-6 on the die.So if you want to find the probability of the multiple of 2 or 3....we have multiplies of 2 in the die from 1-6 which is 2,4 and 6 if you count them they are just 3 numbers and since there is a probability of it to land on any of them it will be 3/6 which is 1/2 if yiu divide by 3 to it's lowest term....Then multiple of 3 is 3,and 6.which will be 2/6 which is 1/3 if u cut to its lowest term. Or in the question means addition sign in probability then it is 2 or 3 which is (1/2)+(1/3)=5/6.Thank you for the question
Answer: 5a: 5/8
Step-by-step explanation: sorry, thats the only one i can read `:)
60% decrease.
$105-$42 = $63
$63/$105 = 0.6
0.6 x 100 = 60