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Evgen [1.6K]
3 years ago
10

How do you approximate a square root to the nearest tenth?

Mathematics
1 answer:
adell [148]3 years ago
3 0
You would get the answer of the square root and round the answer to one decimal place, which is the tenth
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Each morning, Hungry Harry eats some eggs. On any given morning, the number of eggs he eats is equally likely to be 1, 2, 3, 4,
mamaluj [8]

Answer:

Mean = 35

Variance = 291.7

Step-by-step explanation:

Data provided in the question:

X : 1, 2, 3, 4, 5, 6

All the data are independent

Thus,

The mean for this case will be given as:

Mean, E[X] = \frac{\textup{Sum of all the observations}}{\textup{Total number of observations}}

or

 E[X] = \frac{\textup{1+2+3+4+5+6}}{\textup{6}}

or

E[X] = 3.5

For 10 days, Mean = 3.5 × 10 = 35

And,

variance = E[X²] - ( E[X] )²

Now, for this case of independent value,

E[X²] = \frac{1^2+2^2+3^2+4^2+5^2+6^2}{\textup{6}}

or

E[X²] = \frac{1+4+9+16+25+36}{\textup{6}}

or

E[X²] = \frac{91}{\textup{6}}

or

E[X²] = 15.167

Therefore,

variance = E[X²] - ( E[X] )²

or

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or

Variance = 2.917

For 10 days = Variance × Days²

= 2.917 × 10²

= 291.7

3 0
3 years ago
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