Answer:
He will sell 70 bags of popcorn and 105 bottles
Step-by-step explanation:
In 1 day he sells 14 bags of popcorn and 21 bottles
Multiply 14 by 5 which is 70
then multiply the bottles which is 21 by 5 days
105
He will sell 70 bags of popcorn and 105 bottles
Answer:
Case 1:
![AB = 30](https://tex.z-dn.net/?f=AB%20%3D%2030)
![BC = 50](https://tex.z-dn.net/?f=BC%20%3D%2050)
Case 2:
![AB = 15.9](https://tex.z-dn.net/?f=AB%20%3D%2015.9)
![BC = 36.7](https://tex.z-dn.net/?f=BC%20%3D%2036.7)
Case 3: Not possible
Step-by-step explanation:
Given
See attachment for illustration of each case
Required
Find AB and BC
Case 1:
Using Pythagoras theorem in ANB, we have:
![AB^2 = AN^2 + BN^2](https://tex.z-dn.net/?f=AB%5E2%20%3D%20AN%5E2%20%2B%20BN%5E2)
This gives:
![AB^2 = 24^2 + 18^2](https://tex.z-dn.net/?f=AB%5E2%20%3D%2024%5E2%20%2B%2018%5E2)
![AB^2 = 576 + 324](https://tex.z-dn.net/?f=AB%5E2%20%3D%20576%20%2B%20324)
![AB^2 = 900](https://tex.z-dn.net/?f=AB%5E2%20%3D%20900)
Take square roots of both sides
![AB = \sqrt{900](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B900)
![AB = 30](https://tex.z-dn.net/?f=AB%20%3D%2030)
To calculate BC, we consider ANC, where:
![AC^2 = AN^2 + NC^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AN%5E2%20%2B%20NC%5E2)
![40^2 = 24^2 + NC^2](https://tex.z-dn.net/?f=40%5E2%20%3D%2024%5E2%20%2B%20NC%5E2)
![1600 = 576 + NC^2](https://tex.z-dn.net/?f=1600%20%3D%20576%20%2B%20NC%5E2)
Collect like terms
![NC^2 = 1600 - 576](https://tex.z-dn.net/?f=NC%5E2%20%3D%201600%20-%20576)
![NC^2 = 1024](https://tex.z-dn.net/?f=NC%5E2%20%3D%201024)
Take square roots
![NC = \sqrt{1024](https://tex.z-dn.net/?f=NC%20%3D%20%5Csqrt%7B1024)
![NC = 32](https://tex.z-dn.net/?f=NC%20%3D%2032)
So:
![BC = NC + BN](https://tex.z-dn.net/?f=BC%20%3D%20NC%20%2B%20BN)
![BC = 32 + 18](https://tex.z-dn.net/?f=BC%20%3D%2032%20%2B%2018)
![BC = 50](https://tex.z-dn.net/?f=BC%20%3D%2050)
Case 2:
Using Pythagoras theorem in ANB, we have:
![AN^2 = AB^2 + BN^2](https://tex.z-dn.net/?f=AN%5E2%20%3D%20AB%5E2%20%2B%20BN%5E2)
This gives:
![24^2 = AB^2 + 18^2](https://tex.z-dn.net/?f=24%5E2%20%3D%20AB%5E2%20%2B%2018%5E2)
![576 = AB^2 + 324](https://tex.z-dn.net/?f=576%20%3D%20AB%5E2%20%2B%20324)
Collect like terms
![AB^2 = 576 - 324](https://tex.z-dn.net/?f=AB%5E2%20%3D%20576%20-%20324)
![AB^2 = 252](https://tex.z-dn.net/?f=AB%5E2%20%3D%20252)
Take square roots of both sides
![AB = \sqrt{252](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B252)
![AB = 15.9](https://tex.z-dn.net/?f=AB%20%3D%2015.9)
To calculate BC, we consider ABC, where:
![AC^2 = AB^2 + BC^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AB%5E2%20%2B%20BC%5E2)
![40^2 = 252 + BC^2](https://tex.z-dn.net/?f=40%5E2%20%3D%20252%20%2B%20BC%5E2)
![1600 = 252 + BC^2](https://tex.z-dn.net/?f=1600%20%3D%20252%20%2B%20BC%5E2)
Collect like terms
![BC^2 = 1600 - 252](https://tex.z-dn.net/?f=BC%5E2%20%3D%201600%20-%20252)
![BC^2 = 1348](https://tex.z-dn.net/?f=BC%5E2%20%3D%201348)
Take square roots
![BC = \sqrt{1348](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B1348)
![BC = 36.7](https://tex.z-dn.net/?f=BC%20%3D%2036.7)
Case 3:
This is not possible because in ANC
The hypotenuse AN (24) is less than AC (40)
Answer:
x = 14
Step-by-step explanation:
![\frac{150}{84} = \frac{25}{x} \\ \\ 150 \times x = 84 \times 25 \\ \\ x = \frac{84 \times 25}{150} \\ \\ x = \frac{84}{6} \\ \\ x = 14 \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B150%7D%7B84%7D%20%20%3D%20%20%5Cfrac%7B25%7D%7Bx%7D%20%20%5C%5C%20%20%5C%5C%20150%20%5Ctimes%20x%20%3D%2084%20%5Ctimes%2025%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B84%20%5Ctimes%2025%7D%7B150%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B84%7D%7B6%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%2014%20%5C%5C%20)
Answer:
The ratio of smaller rectangle to larger is 1 : 8.
Step-by-step explanation:
Given that:
Area of smaller rectangle = 25 square feet
Area of larger rectangle = 200 square feet
Ratio of areas of these similar rectangles;
Smaller rectangle : Larger rectangle
25 : 200
1 : 8
Hence,
The ratio of smaller rectangle to larger is 1 : 8.
Answer:
y =
x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
To calculate m use the slope formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (- 22, - 14) and (x₂, y₂ ) = (- 18, - 12)
m =
=
= ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
y =
x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
using (- 22, - 14), then
- 14 = - 11 + c ⇒ c = - 14 + 11 = - 3
y =
x - 3 ← in slope- intercept form