F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer:
2 15.50 50
Step-by-step explanation:
took the test
F(x) is most likely the f(f(x)x) where f(x) is g(x))f)) and composition can be 69 + 46 which is the total of 137
Area of a trapezoid is found with the formula, A=(a+b)/2 x h.
Answer:
Step-by-step explanation:
1.
d - 27 = 45
add 27
d = 72
2.
h - 114 = 28
add 114
h = 142
3.
-4 + x = 15
add 4
x = 19
4.
-39 + g = 72
add 39
g = 111
