Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
x = 3(6 + y)/2
Step-by-step explanation:
Solving for x
Add 3y to both sides.
2x = 18 + 3y
Divide both sides by 2.
x = 18 + 3y/2
Factor out the common term 3.
x = 3(6 + y)/2
Answer:
<h2>She gave her brother 6 tickets</h2>
Step-by-step explanation:
This problem is on fractional numbers.
given that she has 60 tickets
1.She used 3/4 of her tickets to play game
=(3/4)*60
=180/4
=45
She is left with (60-45)= 15 tickets
2. She used 1/5 of her remaining tickets for rides
=(1/5)*15
=15/5
=3
She is left with (15-3)= 12 tickets
3. She gave half of her tickets to her brother.
= (1/2)*12
=12/2
= 6
She gave her brother 6 tickets
