Answer:
<h3>9.9s</h3>
Step-by-step explanation:
First note that the river is on the ground level. The height of the river at the ground level is 0
Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552
When h = 0
0 = -16t^2+1552
16t^2 = 1552
t² = 1552/16
t² = 97
t = √97
<em>t = 9.9secs</em>
<em>Hence the time it takes is 9.9secs to the nearest tenth</em>
