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Yeah hannah is right the answer is c
Answer:
0.999999 ≈ 1
Explanation:
In a population ( N ) there is the presence of 2N alleles in the population also chance of fixation can be expressed as ; 1/ 2N
Therefore the probability that the mutation will be lost due to genetic drift
= 2N - 1 / 2N ---- ( 1 )
given that ; N = 100,000
back to equation 1
P ( losing mutation due to genetic drift ) = ((2*100,000) - 1 )) / ( 2* 100,000 )
= ( 200,000 - 1 ) / 200,000
= 0.999999 ≈ 1
