How many inches does 8 centemeters equal?

The amount of money in a savings account after t years is represented by the function f(t)=3600(1.035)t .

timama [110]

Answer: The initial amount in the account = $3600

Step-by-step explanation:

Since we have given that

The amount of money in a savings account after t years is represented by the function

$f(t)=3600(1.035)^t$

As we know the formula "Compound Interest" :

$Amount=P(1+\frac{r}{100})^t\\\\Here,\\\\\text{ P denotes principal}\\\\\text{ R denotes Rate of interest}\\\\\text{ T denotes time}$

So, According to our question,

Rate of interest = 0.35 = 35%

So, equate the both the equations , we get that

Hence, The initial amount in the account = $3600

5 0

3 years ago

Read 2 more answers

Can somebody help me with this?

N76 [4]

Rise is 35, run is 1
35 is the answer

8 0

2 years ago

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11