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inessss [21]
3 years ago
8

Is the molecule shown polar or nonpolar f-o-f

Chemistry
1 answer:
SashulF [63]3 years ago
7 0
It's polar because electronegativities of F and O are different.
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Do you think that the human being is the center of the universe?
Andrej [43]
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3 0
3 years ago
He molecular formula mass of this compound is 180 amu . what are the subscripts in the actual molecular formula?
mezya [45]
I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.

Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol

Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6

Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
<em>Actual molecular formula = C₆H₁₂O₆</em>

5 0
3 years ago
A student observed a chemical reaction in which the mass of the products was measured to be less than the mass of the reactants.
nika2105 [10]

There chemical reactions that can realise or absorb gas to the atmosphere. This means it is harder or impossible to measure it with normal weighing devices and normal taring equipment. As a principal in chemical reactions we have conservation of mass.

5 0
3 years ago
Fe2O3+2Al=Al2O3+2Fe
True [87]
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
= 0.58 x (56 x 2 + 16 x 3)
= 92.8 grams
6 0
3 years ago
Read 2 more answers
What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?
IRINA_888 [86]

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

4.10=-log[H_3O^+]

[H_3O^+]=antilog(-4.10)

[H_3O^+]=7.94\times 10^{-5}

Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

5 0
3 years ago
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