Answer:
Another category of listed hazardous wastes, which can include solvents, are the P- and U-listed hazardous wastes. The P- and U-listed hazardous wastes are specific unused commercial chemical products (CCPs) or manufacturing chemical intermediates that are discarded or intended to be discarded.
Explanation:
hazardous wastes
Answer:
When an atom is in an excited state, the electron can drop all the way to the ground state in one go, or stop on the way in an intermediate level. Electrons do not stay in excited states for very long - they soon return to their ground states, emitting a photon with the same energy as the one that was absorbed.
HOPE IT HELPS
<u>Given:</u>
A → Products
[A] M Rate(M/s)
1. 0.15 0.014
2. 0.30 0.113
3. 0.60 0.905
<u>To determine:</u>
Order of the reaction
<u>Explanation:</u>
The rate of the given reaction can be expressed as:
Rate = k [A]ⁿ-----(1)
where k = rate constant
[A] = concentration of A
n = reaction order
Based on equation (1) the Rates 1 and 2 can be expressed as:
0.014 = k[0.15]ⁿ ------(3)
0.113 = k[0.30]ⁿ-------(4)
Dividing eq (4) by (3) we get:
0.113/0.014 = [0.30/0.15]ⁿ
8 = 2ⁿ
i.e. 2³ = 2ⁿ
n = 3
Ans: Thus, the order of the reaction is 3
Answer:
The answer to your question is T2 = 319.4°K
Explanation:
Data
Volume 1 = V1 = 852 ml
Temperature 1 = T1 = 288°K
Volume 2 = V2 = 945 ml
Temperature 2 = T2 = ?
Process
To solve this problem, use Charles' law.
V1/T1 = V2/T2
-Solve for T2
T2 = V2T1/V1
-Substitution
T2 = (945 x 288) / 852
-Simplification
T2 = 272160 / 852
-Result
T2 = 319.4°K
Answer:
The mass of a solute divided by the mass of a solution times 100
Explanation:
The concentration of a solution refers to how much of a solute is dissolved in an amount of solvent. To express this concentration exist different methods, the mass percent concentration is one of them and is <em>defined as the mass of a solute divided by the mass of a solution times 100:</em>
<em>%m/m= (mass of a solute/mass of solution)x100</em>
<em>Where the mass of the solution is the sum of the mass of solute and mass of solvent.</em>
%m/m is commonly used when you can measure the masses of both solute and solution.
I hope you find this information useful and interesting! Good luck!