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s2008m [1.1K]
3 years ago
8

In the modern periodic table, elements are arranged according to increasing ____. (1 point). . a. atomic number. b. atomic mass.

c. date of discovery. d. electrical conductivity
Chemistry
1 answer:
ki77a [65]3 years ago
5 0
I think the correct answer from the choices listed above is option A. In the modern periodic table, elements are arranged according to increasing <span>atomic number. The atomic number represents the number of protons present for a specific atom.</span>
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The<br> is the continuous movement of water between the<br> atmosphere, the land and the oceans.?
vekshin1

Answer:

hydrologic cycle

Explanation:

7 0
3 years ago
Question 2 of 10
Ganezh [65]
I think A. Molecules interact without bonds breaking
8 0
2 years ago
A concentration cell is built based on the following half reactions by using two pieces of zinc as electrodes, two Zn2+ solution
Lana71 [14]

Explanation:

The given reaction at cathode will be as follows.

At cathode: Zn^{2+} + 2e^{-} \rightarrow Zn,     E_{o} = -0.761 V

At anode: Zn \rightarrow Zn^{2+} + 2e^{-},       E_{o} = 0.761

Therefore, net reaction equation will be as follows.

                 Zn^{2+} + Zn \rightarrow Zn + Zn^{2+}

Initial:     0.129         -            -       0.427

Change:  -0.047      -            -     -0.047

Equilibrium: (0.129 - 0.047)      (0.427 - 0.047)

                = 0.082                       = 0.38

As E^{o}_{cell} for the given reaction is zero.

Hence, equation for calculating new cell potential will be as follows.

                   E_{cell} = E^{o}_{cell} - \frac{RT}{nF} ln \frac{[Zn^{2+}]_{products}}{[Zn^{2+}]_{reactants}}

                              = 0 - \frac{8.314 atm L/mol K \times 291 K}{2 \times 96500} ln \frac{0.38}{0.082}

                              = 0.019

Thus, we can conclude that the cell potential of the given cell is 0.019.

3 0
4 years ago
Convert<br> 12 x 1025 kg/mL to fg/cm3
Anna35 [415]

Answer:

1.2x10^{38}\frac{fg}{cm^3}

Explanation:

Hello there!

In this case, for such unit conversion we need to realize that 1 kg is equal to 1000 g, 1 g is equal to 1x10⁹ and 1 mL equals 1 cm³, therefore we apply:

12x10^{25}kg*\frac{1000g}{1kg} *\frac{1x10^9fg}{1g} *\frac{1mL}{1cm^3} \\\\1.2x10^{38}\frac{fg}{cm^3}

Best regards!

5 0
3 years ago
Which cells from which parts of the body would likely need to use the most energy in a typical day?
Nastasia [14]

Answer:

The muscle cell need to use most entry in a typical day

5 0
3 years ago
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