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bazaltina [42]
4 years ago
7

It has been estimated that an adult T. rex weighed about six tons. Based on that estimate. how many pounds did four adult T.rexe

s weight?
Mathematics
2 answers:
natka813 [3]4 years ago
7 0

1 adult weighs six tons then 4 adults weighs about 24 tons

Ronch [10]4 years ago
3 0
24 tons or 48,000lbs
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It takes 27 pounds of seed to completely plant a 3-acre field. How many pounds of seed are needed per acre?
Ray Of Light [21]

Answer:

9 pounds of seed per acre.

Step-by-step explanation:

All you have to do is division.  It takes 27 pounds of seed to make 3 acres, so 27 divided by 3.  That gives you 9.

5 0
4 years ago
What is the equation of a circle whose center is (2,0) and has a radius= 9?
Flauer [41]
The equation of a circle is: (x - h)² + (y - k)² = radius² where (h, k) is the center. Now just plug in your given information and simplify.

(x - 2)² + (y - 0)² = 9²

Your equation is:
(x - 2)² + y² = 81
6 0
3 years ago
Read 2 more answers
What is 5/12 divided by 3/16 as a fraction?
GuDViN [60]
<span>The answer is
= 20/9
=2 2/9</span>
8 0
3 years ago
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Line segment XY is tangent to circle Z at point U. If the measure of is 84°, what is the measure of ? 42° 84° 96° 168°
Andreas93 [3]

Answer:

The measure of angle YUV is equal to m

Step-by-step explanation:

see the attached figure to better understand the problem

we have that

arc\ UV=84\° -----> given problem

so

m ------> by central angle

we know that

The triangle UZV is an isosceles triangle

because

ZU=ZV=radius

so

m -----> bases angle of the isosceles triangle

Remember that

The sum of the internal angles of a triangle is equal to 180\°

so

m

2m

substitute and solve for m<ZUV

2m

m

m ------> by complementary angles

solve for m<YUZ

48\°+m

m

7 0
3 years ago
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Upper AA 66​-ft-tall fence runs parallel to a wall of a house at a distance of 3030 ft. Find the length of the shortest ladder t
Mkey [24]

Answer:

0.33 ft

Step-by-step explanation:

From the diagram, triangle ACE is similar to triangle BCD.

Therefore,

\frac{b}{30+b} = \frac{6}{a}

a=\frac{6(30+b)}{b}

Let the Length of the Ladder, L

Using Pythagoras theorem

L^{2}=(30+b)^{2}+(\frac{6(30+b)}{b})^{2}

L^{2}=\frac{(30+b)^{2}(36+b^{2})}{b^{2}}

L=\sqrt{\frac{(30+b)^{2}(36+b^{2})}{b^{2}} }

L=\frac{30+b}{b}\sqrt{b^2+36}

To find the least value, we have to equate the derivative of L to 0.

L^{1}=\frac{b^{3}-1080}{b^{2}\sqrt{b^2+36}}

Therefore:

b³-1080=0

b³=1080

b=10.26

The minimum length of the ladder is:

L=\frac{30+10.26}{10.26}\sqrt{10.26^2+36}

=0.33 ft

6 0
3 years ago
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