Answer:
A person can select 3 coins from a box containing 6 different coins in 120 different ways.
Step-by-step explanation:
Total choices = n = 6
no. of selections to be made = r = 3
The order of selection of coins matter so we will use permutation here.
Using the formula of Permutation:
nPr = 
We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.
Order of coin is important means that if we select 3 coins in these two orders:
--> nickel - dime - quarter
--> dime - quarter - nickel
They will count as two different cases.
Calculating the no. of ways 3 coins can be selected from 6 coins.
nPr =
= 
nPr = 120
Answer:
you do not have to state explicitly which limit law(s) you are using. 1 - 5n ... Q: 9) n(x) = 2x - 2 g(x)= x2 + 5 Find h(g(1) A) 5 B) 10 C) 21 D) 40.
Step-by-step explanation:
2 one dollar bills 3 quarters 1 dime and 1 nickel
The answer is : 
Here are the steps below to help you! ^^
The domain of the relation is 7,13 and the range of the relation is 4,20. I hope this helps.