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Sergio [31]
3 years ago
9

There is an 8 cm by 8 cm cube. What is the total surface area of the cube?

Mathematics
2 answers:
kaheart [24]3 years ago
7 0
The total surface area of the 8 cm by 8 cm cube is 384 cm.
Neko [114]3 years ago
6 0

Answer:

384

Step-by-step explanation:

8x8= 64

64x6=384

6 is the number of sides

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Solve for x.<br> 8 + x = -4<br> Answer:
shutvik [7]

Answer:

x = -12

Step-by-step explanation:

Let's solve your equation step-by-step.

8+x=−4

Step 1: Simplify both sides of the equation.

x+8=−4

Step 2: Subtract 8 from both sides.

x+8−8=−4−8

x=−12

7 0
3 years ago
Read 2 more answers
Please help me lol!!!!!!
Virty [35]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
If f(x)=7x+8 and g(x)=x^4, what is (g°f)(0)​
Lina20 [59]
G(f(x))= (7x+8)^4
g(f(x))= (7(0)+8)^4
=(0+8)^4
=8^4
=8•8•8•8
=4,096
8 0
3 years ago
Read 2 more answers
(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)
klemol [59]

Answer:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

Remove parentheses:  (a)=a

=-t^4-5t^3-10t^2+9t^3+3t^2-1

Group like terms

=-t^4-5t^3+9t^3-10t^2+3t^2-1

Add similar elements        

=-t^4-5t^3+9t^3-7t^2-1         ∵ -10t^2+3t^2=-7t^2

Add similar elements        

=-t^4+4t^3-7t^2-1                  ∵  -5t^3+9t^3=4t^3

Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

4 0
3 years ago
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