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Stella [2.4K]
3 years ago
6

Solve and simplify: 4 1/2 x 2 1/3 A.9/2 B.7/3 C.63/6 D.10 1/2

Mathematics
2 answers:
vichka [17]3 years ago
6 0

Answer:

The answer is D. 10 1/2

Step-by-step explanation:

igor_vitrenko [27]3 years ago
5 0

Answer: 10 1/2

Step-by-step explanation:

Convert all mixed numbers into improper fractions

4 1/2 = 9/2

2 1/3 = 7/3

Now multiply 9/2 * 7/3

9*7=63

2*3=6

Get 63/6

Divide 63 and 6 and get 10.5

10.5 will equal to 10 1/2

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7 0
1 year ago
What is the length of BC , rounded to the nearest tenth?
Arte-miy333 [17]

Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

we have

AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

8 0
3 years ago
Read 2 more answers
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